Proposition. Complex Spin in dimension six is \(SL_4\) on a half-spin module [fcap-0034]

Let \(V=W\oplus W'\) be a split nondegenerate complex quadratic space with \(\dim W=3\). For polar-dual bases \(e_i,e'_i\), use \[S^+:(1,e_{12},e_{13},e_{23}),\qquad S^-:(e_{123},-e_3,e_2,-e_1).\] For \(\langle s,t\rangle =[e_{123}]\bigl ( \operatorname {rev}_{\wedge }(s)\wedge t\bigr )\), the second displayed basis is dual to the first, and the full pairing matrix on \(S^+\oplus S^-\) is \[\Omega =\begin {pmatrix}0&I_4\\-I_4&0\end {pmatrix}.\] Clifford generators are self-adjoint for this pairing. Under the paired even-algebra equivalence \(\Phi \) of Theorem [fcap-002V], reversal therefore sends \[(A,D)\longmapsto (D^{\mathsf T},A^{\mathsf T}).\] Thus the even reverse-norm-one group is \[\{(A,A^{-\mathsf T}):A\in GL_4(\mathbb C)\}.\] At this stage it is \(GL_4\), not yet the actual Spin group.

The vector-normalization condition cuts out the determinant-one subgroup. If \(v=\sum _i x_i e_i+y_i e'_i\), its odd Clifford action has block form \[\rho (v)=\begin {pmatrix}0&B_v\\B_v^\sharp &0\end {pmatrix},\] where \[B_v=\begin {pmatrix} 0&-y_3&y_2&-y_1\\ y_3&0&x_1&x_2\\ -y_2&-x_1&0&x_3\\ y_1&-x_2&-x_3&0 \end {pmatrix}.\] These matrices run through all skew \(4\times 4\) matrices. For a skew matrix \(B\), define \(B^\sharp \) by \[\begin {aligned} (B^\sharp )_{01}&=B_{23},& (B^\sharp )_{02}&=-B_{13},& (B^\sharp )_{03}&=B_{12},\\ (B^\sharp )_{12}&=B_{03},& (B^\sharp )_{13}&=-B_{02},& (B^\sharp )_{23}&=B_{01}, \end {aligned}\] with skew extension. Then \((B^\sharp )^\sharp =B\), \(BB^\sharp =-\operatorname {Pf}(B)I\), and \(\operatorname {Pf}(B_v)=-\sum _i x_i y_i\). The last two identities give \(\rho (v)^2=Q(v)I\), matching the Clifford convention.

The complementary-minor identity is \[(ABA^{\mathsf T})^\sharp =\det (A)A^{-\mathsf T}B^\sharp A^{-1}.\] One derivation identifies a skew matrix with an alternating two-form: the operation \(B\mapsto B^\sharp \) is the complementary two-form determined by the ordered volume basis, while \(\bigwedge ^4 A\) multiplies that volume by \(\det A\). Evaluating on basis pairs gives the six coordinate rules above and the displayed identity.

Conjugation by \(\operatorname {diag}(A,A^{-\mathsf T})\) sends the two off-diagonal blocks to \[ABA^{\mathsf T},\qquad A^{-\mathsf T}B^\sharp A^{-1}.\] By the complementary-minor identity, it preserves the vector graph \(\{(B,B^\sharp ):B^{\mathsf T}=-B\}\) exactly when \(\det A=1\). Sufficiency is immediate. For necessity, choose any nonzero \(B^\sharp \); equality of the two lower blocks forces \(\det A=1\). Faithfulness of the full Clifford action in this even dimension lifts this matrix statement to normalization of the actual vector subspace.

Every Spin element therefore acts on \(S^+\) through \(SL_4(\mathbb C)\). Conversely, for \(A\in SL_4(\mathbb C)\), let \(x\) be the unique even Clifford preimage of \((A,A^{-\mathsf T})\). It has reverse norm one and, by the graph calculation, normalizes \(V\). The carrier-completion argument of Proposition [fcap-0032] places \(x\) in actual Spin. The mutually inverse maps are \[g\longmapsto \rho _+(g),\qquad A\longmapsto \Phi ^{-1}(A,A^{-\mathsf T}).\] Hence \[\operatorname {Spin}_6(\mathbb C)\simeq SL_4(\mathbb C).\] In the displayed bases \(S^+\) is the standard four-dimensional module and \(S^-\) is its dual.

[fulton2004representation, Exercise 20.39, p. 311] give the group and standard \(S^+\) module. [goodman2009symmetry, Section 6.3.3, Exercise 1, p. 322] independently give the same complex group. Here the cross-pairing proves \(S^-\) is dual, and the vector-graph calculation proves the actual image.

[meinrenken2013clifford, Section 3.7.6, p. 84] gives the compact real form \(\operatorname {Spin}(6)=SU(4)\).

TauCeti formalizes the paired half-spin algebra and matrix equivalences TauCeti.SpinPolarizationData.evenCliffordEquivProdEnd TauCeti.SpinPolarizationData.evenCliffordEquivProdMatrix. The vector graph, determinant-one group image and inverse are proved above, not by these declarations.