Characteristic-two tensor kernel (Zhou §2) [connes-0011]
✍️sourceAGENTDRAFTED
Characteristic-two tensor kernel (Zhou §2) [connes-0011]
✍️sourceAGENTDRAFTED
1. Tensor retraction in characteristic two [connes-001E]AGENTDRAFTED
1. Tensor retraction in characteristic two [connes-001E]AGENTDRAFTED
Lemma. Characteristic-two tensor retraction [connes-000C]
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Lemma. Characteristic-two tensor retraction [connes-000C]
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Let \(k=\mathbb F_2\), \(A=k[t]^3\), and let \[C=(A\otimes _k A)^{\mathrm {Flip}}.\] The diagonal function \(\Delta (a)=a\otimes a\) lands in \(C\). Although \(\Delta \) is not a linear map, Zhou's characteristic-two calculation produces a surjective linear retraction \(\delta :C\to A\) satisfying \(\delta (\Delta (a))=a\) [zhou2026icc, Section 2, Lemma 2.1]. The retraction is equivariant for the diagonal \(\mathrm {SL}_3(k[t])\)-action.
2. Formalizing the characteristic-two retraction [connes-000U]
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2. Formalizing the characteristic-two retraction [connes-000U]
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The Lean carriers and diagonal for Lemma [connes-000C] are
The implementation fixes the standard polynomial and coordinate bases. It takes the coefficientwise Hadamard product on \(k[t]\), applies it in the three coordinates of \(A\), lifts the resulting bilinear map through the tensor product, and restricts it to \(C\). The Boolean identity \(x^2=x\) gives \(\delta (a\otimes a)=a\).
The basis-dependent formula implements a basis-free role: a linear left
inverse to the diagonal squares, equivariant for the diagonal
\(\mathrm {SL}_3(k[t])\)-action. Equivariance is not proved by expanding an
arbitrary fixed tensor. The submodule
The basis calculation in
SquareSpanData interface therefore hides the coordinates from later
sections. Consumers need only the spanning result, so a future basis-free
construction could replace the formula without changing the action or theorem
interfaces.