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Mathlib.Analysis.BoxIntegral.Partition.SubboxInduction

Induction on subboxes #

In this file we prove (see BoxIntegral.Box.exists_taggedPartition_isHenstock_isSubordinate_homothetic) that for every box I in ℝⁿ and a function r : ℝⁿ → ℝ positive on I there exists a tagged partition π of I such that

Later we will use this lemma to prove that the Henstock filter is nontrivial, hence the Henstock integral is well-defined.

Tags #

partition, tagged partition, Henstock integral

Split a box in ℝⁿ into 2 ^ n boxes by hyperplanes passing through its center.

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    theorem BoxIntegral.Box.subbox_induction_on {ι : Type u_1} [Fintype ι] {p : BoxIntegral.Box ιProp} (I : BoxIntegral.Box ι) (H_ind : (J : BoxIntegral.Box ι) → J I((J' : BoxIntegral.Box ι) → J' BoxIntegral.Prepartition.splitCenter Jp J') → p J) (H_nhds : ∀ (z : ι), z BoxIntegral.Box.Icc IU, U nhdsWithin z (BoxIntegral.Box.Icc I) ((J : BoxIntegral.Box ι) → J I(m : ) → z BoxIntegral.Box.Icc JBoxIntegral.Box.Icc J U(∀ (i : ι), BoxIntegral.Box.upper J i - BoxIntegral.Box.lower J i = (BoxIntegral.Box.upper I i - BoxIntegral.Box.lower I i) / 2 ^ m) → p J)) :
    p I

    Let p be a predicate on Box ι, let I be a box. Suppose that the following two properties hold true.

    • Consider a smaller box J ≤ I. The hyperplanes passing through the center of J split it into 2 ^ n boxes. If p holds true on each of these boxes, then it true on J.
    • For each z in the closed box I.Icc there exists a neighborhood U of z within I.Icc such that for every box J ≤ I such that z ∈ J.Icc ⊆ U, if J is homothetic to I with a coefficient of the form 1 / 2 ^ m, then p is true on J.

    Then p I is true. See also BoxIntegral.Box.subbox_induction_on' for a version using BoxIntegral.Box.splitCenterBox instead of BoxIntegral.Prepartition.splitCenter.

    Given a box I in ℝⁿ and a function r : ℝⁿ → (0, ∞), there exists a tagged partition π of I such that

    • π is a Henstock partition;
    • π is subordinate to r;
    • each box in π is homothetic to I with coefficient of the form 1 / 2 ^ m.

    This lemma implies that the Henstock filter is nontrivial, hence the Henstock integral is well-defined.

    Given a box I in ℝⁿ, a function r : ℝⁿ → (0, ∞), and a prepartition π of I, there exists a tagged prepartition π' of I such that

    • each box of π' is included in some box of π;
    • π' is a Henstock partition;
    • π' is subordinate to r;
    • π' covers exactly the same part of I as π;
    • the distortion of π' is equal to the distortion of π.

    Given a prepartition π of a box I and a function r : ℝⁿ → (0, ∞), π.toSubordinate r is a tagged partition π' such that

    • each box of π' is included in some box of π;
    • π' is a Henstock partition;
    • π' is subordinate to r;
    • π' covers exactly the same part of I as π;
    • the distortion of π' is equal to the distortion of π.
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      Given a tagged prepartition π₁, a prepartition π₂ that covers exactly I \ π₁.iUnion, and a function r : ℝⁿ → (0, ∞), returns the union of π₁ and π₂.toSubordinate r. This partition π has the following properties:

      • π is a partition, i.e. it covers the whole I;
      • π₁.boxes ⊆ π.boxes;
      • π.tag J = π₁.tag J whenever J ∈ π₁;
      • π is Henstock outside of π₁: π.tag J ∈ J.Icc whenever J ∈ π, J ∉ π₁;
      • π is subordinate to r outside of π₁;
      • the distortion of π is equal to the maximum of the distortions of π₁ and π₂.
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