Auxiliary for List.reverse
. List.reverseAux l r = l.reverse ++ r
, but it is defined directly.
Equations
- List.reverseAux [] x = x
- List.reverseAux (a :: l) x = List.reverseAux l (a :: x)
Instances For
O(|as|)
. Reverse of a list:
[1, 2, 3, 4].reverse = [4, 3, 2, 1]
Note that because of the "functional but in place" optimization implemented by Lean's compiler, this function works without any allocations provided that the input list is unshared: it simply walks the linked list and reverses all the node pointers.
Equations
- List.reverse as = List.reverseAux as []
Instances For
O(|xs|)
: append two lists. [1, 2, 3] ++ [4, 5] = [1, 2, 3, 4, 5]
.
It takes time proportional to the first list.
Equations
- List.append [] x = x
- List.append (a :: l) x = a :: List.append l x
Instances For
Tail-recursive version of List.append
.
Equations
- List.appendTR as bs = List.reverseAux (List.reverse as) bs
Instances For
Equations
- List.instEmptyCollectionList = { emptyCollection := [] }
O(|l|)
. erase l a
removes the first occurrence of a
from l
.
Equations
- List.erase [] x = []
- List.erase (a :: as) x = match a == x with | true => as | false => a :: List.erase as x
Instances For
O(i)
. eraseIdx l i
removes the i
'th element of the list l
.
erase [a, b, c, d, e] 0 = [b, c, d, e]
erase [a, b, c, d, e] 1 = [a, c, d, e]
erase [a, b, c, d, e] 5 = [a, b, c, d, e]
Equations
- List.eraseIdx [] x = []
- List.eraseIdx (head :: as) 0 = as
- List.eraseIdx (a :: as) (Nat.succ n) = a :: List.eraseIdx as n
Instances For
Tail-recursive version of List.map
.
Equations
- List.mapTR f as = List.mapTR.loop f as []
Instances For
Equations
- List.mapTR.loop f [] x = List.reverse x
- List.mapTR.loop f (a :: as) x = List.mapTR.loop f as (f a :: x)
Instances For
O(|l|)
. filterMap f l
takes a function f : α → Option β
and applies it to each element of l
;
the resulting non-none
values are collected to form the output list.
filterMap
(fun x => if x > 2 then some (2 * x) else none)
[1, 2, 5, 2, 7, 7]
= [10, 14, 14]
Equations
- List.filterMap f [] = []
- List.filterMap f (head :: tail) = match f head with | none => List.filterMap f tail | some b => b :: List.filterMap f tail
Instances For
O(|l|)
. filter f l
returns the list of elements in l
for which f
returns true.
filter (· > 2) [1, 2, 5, 2, 7, 7] = [5, 7, 7]
Equations
- List.filter p [] = []
- List.filter p (head :: tail) = match p head with | true => head :: List.filter p tail | false => List.filter p tail
Instances For
Tail-recursive version of List.filter
.
Equations
- List.filterTR p as = List.filterTR.loop p as []
Instances For
Equations
- List.filterTR.loop p [] x = List.reverse x
- List.filterTR.loop p (a :: l) x = match p a with | true => List.filterTR.loop p l (a :: x) | false => List.filterTR.loop p l x
Instances For
O(|l|)
. partition p l
calls p
on each element of l
, partitioning the list into two lists
(l_true, l_false)
where l_true
has the elements where p
was true
and l_false
has the elements where p
is false.
partition p l = (filter p l, filter (not ∘ p) l)
, but it is slightly more efficient
since it only has to do one pass over the list.
partition (· > 2) [1, 2, 5, 2, 7, 7] = ([5, 7, 7], [1, 2, 2])
Equations
- List.partition p as = List.partition.loop p as ([], [])
Instances For
Equations
- List.partition.loop p [] (bs, cs) = (List.reverse bs, List.reverse cs)
- List.partition.loop p (a :: as) (bs, cs) = match p a with | true => List.partition.loop p as (a :: bs, cs) | false => List.partition.loop p as (bs, a :: cs)
Instances For
O(|l|)
. dropWhile p l
removes elements from the list until it finds the first element
for which p
returns false; this element and everything after it is returned.
dropWhile (· < 4) [1, 3, 2, 4, 2, 7, 4] = [4, 2, 7, 4]
Equations
- List.dropWhile p [] = []
- List.dropWhile p (head :: tail) = match p head with | true => List.dropWhile p tail | false => head :: tail
Instances For
O(|l|)
. find? p l
returns the first element for which p
returns true,
or none
if no such element is found.
Equations
- List.find? p [] = none
- List.find? p (head :: tail) = match p head with | true => some head | false => List.find? p tail
Instances For
O(|l|)
. findSome? f l
applies f
to each element of l
, and returns the first non-none
result.
findSome? (fun x => if x < 5 then some (10 * x) else none) [7, 6, 5, 8, 1, 2, 6] = some 10
Equations
- List.findSome? f [] = none
- List.findSome? f (head :: tail) = match f head with | some b => some b | none => List.findSome? f tail
Instances For
O(|l|)
. replace l a b
replaces the first element in the list equal to a
with b
.
replace [1, 4, 2, 3, 3, 7] 3 6 = [1, 4, 2, 6, 3, 7]
replace [1, 4, 2, 3, 3, 7] 5 6 = [1, 4, 2, 3, 3, 7]
Equations
- List.replace [] x x = []
- List.replace (a :: as) x x = match a == x with | true => x :: as | false => a :: List.replace as x x
Instances For
O(|l|)
. elem a l
or l.contains a
is true if there is an element in l
equal to a
.
Equations
- List.contains as a = List.elem a as
Instances For
- head: ∀ {α : Type u} {a : α} (as : List α), List.Mem a (a :: as)
The head of a list is a member:
a ∈ a :: as
. - tail: ∀ {α : Type u} {a : α} (b : α) {as : List α}, List.Mem a as → List.Mem a (b :: as)
A member of the tail of a list is a member of the list:
a ∈ l → a ∈ b :: l
.
a ∈ l
is a predicate which asserts that a
is in the list l
.
Unlike elem
, this uses =
instead of ==
and is suited for mathematical reasoning.
a ∈ [x, y, z] ↔ a = x ∨ a = y ∨ a = z
Instances For
Equations
- List.instMembershipList = { mem := List.Mem }
Equations
- List.instDecidableMemListInstMembershipList a as = decidable_of_decidable_of_iff (_ : List.elem a as = true ↔ a ∈ as)
O(|l|^2)
. Erase duplicated elements in the list.
Keeps the first occurrence of duplicated elements.
eraseDups [1, 3, 2, 2, 3, 5] = [1, 3, 2, 5]
Equations
- List.eraseDups as = List.eraseDups.loop as []
Instances For
Equations
- List.eraseDups.loop [] x = List.reverse x
- List.eraseDups.loop (a :: l) x = match List.elem a x with | true => List.eraseDups.loop l x | false => List.eraseDups.loop l (a :: x)
Instances For
O(|l|)
. Erase repeated adjacent elements. Keeps the first occurrence of each run.
eraseReps [1, 3, 2, 2, 2, 3, 5] = [1, 3, 2, 3, 5]
Equations
- List.eraseReps x = match x with | [] => [] | a :: as => List.eraseReps.loop a as []
Instances For
Equations
- List.eraseReps.loop x [] x = List.reverse (x :: x)
- List.eraseReps.loop x (a' :: as) x = match x == a' with | true => List.eraseReps.loop x as x | false => List.eraseReps.loop a' as (x :: x)
Instances For
O(|l|)
. span p l
splits the list l
into two parts, where the first part
contains the longest initial segment for which p
returns true
and the second part is everything else.
span (· > 5) [6, 8, 9, 5, 2, 9] = ([6, 8, 9], [5, 2, 9])
span (· > 10) [6, 8, 9, 5, 2, 9] = ([6, 8, 9, 5, 2, 9], [])
Equations
- List.span p as = List.span.loop p as []
Instances For
Equations
- List.span.loop p [] x = (List.reverse x, [])
- List.span.loop p (a :: l) x = match p a with | true => List.span.loop p l (a :: x) | false => (List.reverse x, a :: l)
Instances For
O(|l|)
. groupBy R l
splits l
into chains of elements
such that adjacent elements are related by R
.
groupBy (·==·) [1, 1, 2, 2, 2, 3, 2] = [[1, 1], [2, 2, 2], [3], [2]]
groupBy (·<·) [1, 2, 5, 4, 5, 1, 4] = [[1, 2, 5], [4, 5], [1, 4]]
Equations
- List.groupBy R x = match x with | [] => [] | a :: as => List.groupBy.loop R as a [] []
Instances For
Equations
- List.groupBy.loop R (a :: as) x x x = match R x a with | true => List.groupBy.loop R as a (x :: x) x | false => List.groupBy.loop R as a [] (List.reverse (x :: x) :: x)
- List.groupBy.loop R [] x x x = List.reverse (List.reverse (x :: x) :: x)
Instances For
O(|l|)
. lookup a l
treats l : List (α × β)
like an association list,
and returns the first β
value corresponding to an α
value in the list equal to a
.
Equations
- List.lookup x [] = none
- List.lookup x ((k, b) :: es) = match x == k with | true => some b | false => List.lookup x es
Instances For
O(|xs|)
. Computes the "set difference" of lists,
by filtering out all elements of xs
which are also in ys
.
removeAll [1, 1, 5, 1, 2, 4, 5] [1, 2, 2] = [5, 4, 5]
Equations
- List.removeAll xs ys = List.filter (fun x => List.notElem x ys) xs
Instances For
O(|xs|)
. Returns the longest initial segment of xs
for which p
returns true.
Equations
- List.takeWhile p [] = []
- List.takeWhile p (head :: tail) = match p head with | true => head :: List.takeWhile p tail | false => []
Instances For
O(|l|)
. Applies function f
to all of the elements of the list, from right to left.
foldr f init [a, b, c] = f a <| f b <| f c <| init
Equations
- List.foldr f init [] = init
- List.foldr f init (head :: tail) = f head (List.foldr f init tail)
Instances For
O(min |xs| |ys|)
. Applies f
to the two lists in parallel, stopping at the shorter list.
zipWith f [x₁, x₂, x₃] [y₁, y₂, y₃, y₄] = [f x₁ y₁, f x₂ y₂, f x₃ y₃]
Equations
- List.zipWith f (x_2 :: xs) (y :: ys) = f x_2 y :: List.zipWith f xs ys
- List.zipWith f x x = []
Instances For
O(min |xs| |ys|)
. Combines the two lists into a list of pairs, with one element from each list.
The longer list is truncated to match the shorter list.
zip [x₁, x₂, x₃] [y₁, y₂, y₃, y₄] = [(x₁, y₁), (x₂, y₂), (x₃, y₃)]
Equations
- List.zip = List.zipWith Prod.mk
Instances For
O(|l|)
. Separates a list of pairs into two lists containing the first components and second components.
unzip [(x₁, y₁), (x₂, y₂), (x₃, y₃)] = ([x₁, x₂, x₃], [y₁, y₂, y₃])
Equations
- List.unzip [] = ([], [])
- List.unzip ((a, b) :: t) = match List.unzip t with | (al, bl) => (a :: al, b :: bl)
Instances For
O(n)
. range n
is the numbers from 0
to n
exclusive, in increasing order.
range 5 = [0, 1, 2, 3, 4]
Equations
- List.range n = List.range.loop n []
Instances For
Equations
- List.range.loop 0 x = x
- List.range.loop (Nat.succ n) x = List.range.loop n (n :: x)
Instances For
Equations
- List.iotaTR.go 0 x = List.reverse x
- List.iotaTR.go (Nat.succ n) x = List.iotaTR.go n (Nat.succ n :: x)
Instances For
O(|l|)
. enumFrom n l
is like enum
but it allows you to specify the initial index.
enumFrom 5 [a, b, c] = [(5, a), (6, b), (7, c)]
Equations
- List.enumFrom x [] = []
- List.enumFrom x (x_2 :: xs) = (x, x_2) :: List.enumFrom (x + 1) xs
Instances For
O(|l|)
. intersperse sep l
alternates sep
and the elements of l
:
intersperse sep [] = []
intersperse sep [a] = [a]
intersperse sep [a, b] = [a, sep, b]
intersperse sep [a, b, c] = [a, sep, b, sep, c]
Equations
- List.intersperse sep [] = []
- List.intersperse sep [x_1] = [x_1]
- List.intersperse sep (x_1 :: xs) = x_1 :: sep :: List.intersperse sep xs
Instances For
O(|xs|)
. intercalate sep xs
alternates sep
and the elements of xs
:
intercalate sep [] = []
intercalate sep [a] = a
intercalate sep [a, b] = a ++ sep ++ b
intercalate sep [a, b, c] = a ++ sep ++ b ++ sep ++ c
Equations
- List.intercalate sep xs = List.join (List.intersperse sep xs)
Instances For
bind xs f
is the bind operation of the list monad. It applies f
to each element of xs
to get a list of lists, and then concatenates them all together.
Instances For
- nil: ∀ {α : Type u} [inst : LT α] (b : α) (bs : List α), List.lt [] (b :: bs)
[]
is the smallest element in the order. - head: ∀ {α : Type u} [inst : LT α] {a : α} (as : List α) {b : α} (bs : List α), a < b → List.lt (a :: as) (b :: bs)
If
a < b
thena::as < b::bs
. - tail: ∀ {α : Type u} [inst : LT α] {a : α} {as : List α} {b : α} {bs : List α},
¬a < b → ¬b < a → List.lt as bs → List.lt (a :: as) (b :: bs)
If
a
andb
are equivalent andas < bs
, thena::as < b::bs
.
The lexicographic order on lists.
[] < a::as
, and a::as < b::bs
if a < b
or if a
and b
are equivalent and as < bs
.
Instances For
Equations
isPrefixOf l₁ l₂
returns true
Iff l₁
is a prefix of l₂
.
That is, there exists a t
such that l₂ == l₁ ++ t
.
Equations
- List.isPrefixOf [] x = true
- List.isPrefixOf x [] = false
- List.isPrefixOf (a :: as) (b :: bs) = (a == b && List.isPrefixOf as bs)
Instances For
isPrefixOf? l₁ l₂
returns some t
when l₂ == l₁ ++ t
.
Equations
- List.isPrefixOf? [] x = some x
- List.isPrefixOf? x [] = none
- List.isPrefixOf? (a :: as) (b :: bs) = if (a == b) = true then List.isPrefixOf? as bs else none
Instances For
isSuffixOf l₁ l₂
returns true
Iff l₁
is a suffix of l₂
.
That is, there exists a t
such that l₂ == t ++ l₁
.
Equations
- List.isSuffixOf l₁ l₂ = List.isPrefixOf (List.reverse l₁) (List.reverse l₂)
Instances For
isSuffixOf? l₁ l₂
returns some t
when l₂ == t ++ l₁
.
Equations
- List.isSuffixOf? l₁ l₂ = Option.map List.reverse (List.isPrefixOf? (List.reverse l₁) (List.reverse l₂))
Instances For
O(min |as| |bs|)
. Returns true if as
and bs
have the same length,
and they are pairwise related by eqv
.
Equations
- List.isEqv [] [] x = true
- List.isEqv (a :: as) (b :: bs) x = (x a b && List.isEqv as bs x)
- List.isEqv x x x = false
Instances For
replicate n a
is n
copies of a
:
replicate 5 a = [a, a, a, a, a]
Equations
- List.replicate 0 x = []
- List.replicate (Nat.succ n) x = x :: List.replicate n x
Instances For
Tail-recursive version of List.replicate
.
Equations
- List.replicateTR n a = List.replicateTR.loop a n []
Instances For
Equations
- List.replicateTR.loop a 0 x = x
- List.replicateTR.loop a (Nat.succ n) x = List.replicateTR.loop a n (a :: x)
Instances For
Removes the last element of the list.
Equations
- List.dropLast [] = []
- List.dropLast [x_1] = []
- List.dropLast (x_1 :: xs) = x_1 :: List.dropLast xs
Instances For
Returns the largest element of the list, if it is not empty.
Equations
- List.maximum? x = match x with | [] => none | a :: as => some (List.foldl max a as)
Instances For
Returns the smallest element of the list, if it is not empty.
Equations
- List.minimum? x = match x with | [] => none | a :: as => some (List.foldl min a as)